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This is a discussion on another stupid question ... within the Interior Mods forums, part of the Tech & Modifying & General Repairs category; whats better 300 x 1 at 4 Ohms Mono or 1200 x 1 at 1 Ohm Mono thanx...

  1. #1
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    another stupid question ...

    whats better 300 x 1 at 4 Ohms Mono or 1200 x 1 at 1 Ohm Mono
    thanx
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  3. #2
    Registered User bdoug's Avatar
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    Well, more power is always better However, if you don't give the 1200 W amp a 1 ohm load, it won't produce 1200 W.

    You want to match the ohm load of you subwoofers to the amp you are buying.

    You can wire subs in either parallel or series. Parallel reduces the ohm load and series increases the ohm load. Wiring two 4 ohm subs in parallel (or a single sub with dual 4 ohm coils) produces a 2 ohm load. Wiring two 4 ohm subs in series (or a single sub with dual 4 ohm coils) produces a 8 ohm load.


    JL Audio wrote a good article on sub wiring here http://www.jlaudio.com/tutorials/wiring/index.html
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  4. #3
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    so if i run my audiobahn 1300hct amp with 1 12" infinity kappa perfect vq at 300 x 1 at 4 Ohms Mono it will sound really good?
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  5. #4
    Registered User Th3Franz's Avatar
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    yeah it should sound fine. Is the amp specified to be 1-ohm stable? just wondering.
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  6. #5
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    i would think so heres the link to it http://www.audio-warehouse.com/web/m...HCT/detail.asp and heres something else

    300 x 1 at 4 Ohms Mono
    600 x 1 at 2 Ohms Mono
    1200 x 1 at 1 Ohm Mono
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  7. #6
    Registered User Shawn's Avatar
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    Remember that most subs are Dual Voice Coils, which means one 4 ohm DVC sub can alone be wired in parallel down to 2 ohms. And 2 DVC 4 ohm subs can together be wired to 1 ohm.

    total resistance = 1/(1/x + 1/x + ...) where x is the resistance of each voice coil.

    (ie: for 2 4 ohm DVC subs: 1/(1/4 + 1/4 + 1/4 + 1/4) => 1/1 = 1 ohm )

    in my last setup I had 3 DVC subs at 6 ohms each, total load was down to 1 ohm.
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  8. #7
    Registered User Th3Franz's Avatar
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    I believe you can also wire three dual voice coil subs to be 2.667 ohms. If you were to run that at 1 ohm, I'd be wary. Audiobahn doesn't make the most efficient amps, and lower impedance (higher power), the more heat that amp is going to produce. Start out at 4-ohms and see how that is for loudness and sound quality. With lower impedance, you can lose sound quality.

    Oh, and also, I hope you don't plan on buying your amp online. Audiobahn had a specific warning on their web site not to buy from online retailers. The main reason is that only authorized retailers will get a manufacturer warranty on the products they sell. So, if you buy an amp from an online retailer that isn't authorized, you probably won't get any warranty support from Audiobahn.

    Good luck.
    Last edited by Th3Franz; 08-27-2003 at 12:20 AM.
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  9. #8
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    im buying it thru my work circuit city ... at cost
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  10. #9
    Registered User Th3Franz's Avatar
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    Very nice. If you don't mind my asking, how much are you getting it for?
    - F r a n z
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  11. #10
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    the 1300hct ill be getting for 320 and the infinity kappa perfect vq 12 inch 145
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  12. #11
    Registered User Shadow's Avatar
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    Originally posted by Shawn
    total resistance = 1/(1/x + 1/x + ...) where x is the resistance of each voice coil.

    (ie: for 2 4 ohm DVC subs: 1/(1/4 + 1/4 + 1/4 + 1/4) => 1/1 = 1 ohm )

    in my last setup I had 3 DVC subs at 6 ohms each, total load was down to 1 ohm.
    It's so nice to see some practical elements of electrical engineering on the internet. It warms the heart of this electrical engineer.

    A shortcut for the formula posted by Shawn is:

    R(total) = (R1 x R2 x ... x Rn)/(R1 + R2 + ... + Rn)

    e.g. (4 * 4)/(4 + 4) = 16/8 = 2

    -Shadow
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  13. #12
    Registered User Shawn's Avatar
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    Originally posted by Shadow
    A shortcut for the formula posted by Shawn is:

    R(total) = (R1 x R2 x ... x Rn)/(R1 + R2 + ... + Rn)

    e.g. (4 * 4)/(4 + 4) = 16/8 = 2

    -Shadow
    Hehe, don't be too sneaky. That equation only applies when there is two ciruits, or voice coils in this case(1 DVC sub).

    When you deal with 3 for example, the equaton is:

    R1 * R2 * R3
    Rt = --------------------------------
    R1*R2 + R1*R3 + R2*R3

    I think it keeps getting nastier as you include more voice coils. I think the easiest way with 3 or more voice coils is when you can use the 'product-over-sum' rule to find the parallel resistance of R1 and R2, then use it again to find the parallel resistance of that with R3, etc.
    But is that really easier than the first equation? hehe
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  14. #13
    Registered User Shadow's Avatar
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    Originally posted by Shawn
    Hehe, don't be too sneaky. That equation only applies when there is two ciruits, or voice coils in this case(1 DVC sub).

    When you deal with 3 for example, the equaton is:

    R1 * R2 * R3
    Rt = --------------------------------
    R1*R2 + R1*R3 + R2*R3

    I think it keeps getting nastier as you include more voice coils. I think the easiest way with 3 or more voice coils is when you can use the 'product-over-sum' rule to find the parallel resistance of R1 and R2, then use it again to find the parallel resistance of that with R3, etc.
    But is that really easier than the first equation? hehe
    You are correct. I wrote that equation wrong. It should be the following:

    R(total) = (R1 * R2) / (R1 + R2)

    It doesn't matter how many resistors (re: loads) you have in parallel because you can reduce them in pairs using the above equation until you reach the total resistance. For example:

    R1 = 4
    R2 = 4
    R3 = 4

    R(12) = (4 * 4) / (4 + 4) = 2
    R(total) = (2 * 4) / (2 + 4) = 4/3

    Sorry about the mistake. I need to look back in my Basic Circuits book once and a while. You really do forget things when you leave school.

    -Shadow
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