This is a discussion on Audi A4 1.8 "300hp man!" within the Comparison: WRX vs World forums, part of the Community - Meet other Enthusiasts category; Originally Posted by Wrinklechops I agree. Apples and oranges, kinda. A JDM 2.0 for us might be a different story. ...
Also, the 2.5 will put out mad torque over the Evo's 2.0 any day of the week. That's a double edged sword though, because our 2.5 will in turn tear our transmissions up much quicker than even a WRX's 2.0, much less an Evo's 2.0.
So I stand corrected maybe...displacement = torque. At the end of the day, which do you want, more torque or more horsepower?
You're just saying that you dropped big money when it doesn't seem like you did at all. 260whp just sounds like a half assed setup to me.
260whp in my WRX would seem like a lot to me.
Grandfather of the Bugeye Mafia
2013 Subaru BRZ Limited
2002 Subaru WRX Bugeyebrid Wagon
Dear gosh, anyone else noticing the mad quote mess-ups?
I know you know this... but you'll put down similar, if not almost identical numbers. Power wise the 2.0 is very similar to the 2.5, but there's a large torque difference between the EJ205, and EJ255/EJ257.
It's simple... Horsepower is generated through torque at RPMs... torque is generated by a larger stroke volume.
Since the 2.0L with the same amount of boost will always have a lower stroke volume.. then they'll never be able to produce a larger amount of torque with the same modifications.
A GREAT example of this is the 8.3L v10 viper engine, vs the 5.0L v10 M5 engine. Both produce 500 horsepower, but the torque on the viper's engine is approximately 600tq and the M5's engine is approximately 385tq.
I understand that they are very different engine technologies, but with identical engine technologies, a large volume engine will always produce more torque.
Now to go back to my original statement that power is produced by torque at RPM... well since the M5 has very little torque... it must get it's horsepower at a high rpm, correct?? Correct. 7750rpm is where the peak horsepower on an M5 is achieved. The viper's peak is right above 5000rpm because it produces larger amounts of torque.
Now the exact equation of horsepower is: (Torque x Engine Speed) / 5252 = Horsepower
If you want to know where 5252 comes from I can explain it.. but it is slightly complex, and easily found with google.
The point of me posting the equation is to show you that Torque x Engine speed is where we get the power... the more engine speed at a set torque, then the more power you can achieve.
Now obviously torque isn't a set number.. where does that come into play?
Torque = Force X Radius.
The crankshafts are the same radius on the 2.0L and 2.5L engines.. correct? correct... so that means that to establish more torque, you need more stroke volume because it'll create a higher force. In addition, compression creates more force.. but the 2.0L and 2.5L are the same compression. So where does the equivalent power come from on the 2.0L and the 2.5L engines?
The 2.0L engine is at the top... with the 2.5L engine directly below:
227 hp (169 kW) at 6000 rpm with 217 lb·ft (294 N·m) at 4000 rpm
230 hp (172 kW) at 5600 rpm with 235 lb·ft (319 N·m) at 3600 rpm
Obviously power is achieved lower, and torque is achieved lower because a larger volume in the cylinder, but the horsepower is still achieved on the 2.0L because it's found 400rpm later. Again back to horsepower = torque x engine speed / 5252. So even with the slightly lower torque, the engine speed makes up the horsepower with a higher powerband.
Does this make sense? Or am I talking in "Jibba Jabba"